System of Linear Equations MCQ Quiz - Objective Question with Answer for System of Linear Equations - Download Free PDF

Last updated on Apr 5, 2025

Latest System of Linear Equations MCQ Objective Questions

System of Linear Equations Question 1:

Consider the following system of equations in three real variables x, y, z.

2x – 3y + 7z = 5

3x + y – 3z = 13

2x + 19y – 47z = 32

The system of equation has

A. No Solution

B. A Unique Solution

C. More than one but finite number of solutions

D. More than two but finite number of solutions

  1. Either A or D is correct
  2. Either B or C is correct
  3. Either C or D is correct
  4. Either B or D is correct 
  5. Either A or C is correct 

Answer (Detailed Solution Below)

Option 5 : Either A or C is correct 

System of Linear Equations Question 1 Detailed Solution

Explanation:

Augmented matrix will be

R3 → R3 – R1

R2 → 2R2 – 3R1

R3 → R3 – 2R2

Rank of A ≠ Rank of Augmented matrix.

Hence given system of equations has no solution.

Hence Option(5) is the correct answer.

System of Linear Equations Question 2:

Consider the following system of linear equations

x + y + 5z = 3, x + 2y + mz = 5 and x + 2y + 4z = k.

The system is consistent if 

  1. m ≠ 4
  2. k ≠ 5
  3. m = 4
  4. k = 5

Answer (Detailed Solution Below)

Option :

System of Linear Equations Question 2 Detailed Solution

Explanation:

Consider the augmented matrix  

  

Applying  row operations: 
 

  

  

  

The system is consistent if and only if  

If    , then    for any value of k 

Hence, option (1) is true

If k = 5 , then    for any value of m

Hence, option (4) is true.  

If    and m = 4 , then \rho(A) = 2 \) ,   

and the system will be inconsistent.  

Hence, options (1) and (4) are  correct.

System of Linear Equations Question 3:

What will be the conditions on p, q, r so that the linear system of equations

x + 2y – 3z = p

2x + 6y – 11z = q

x – 2y + 7z = r

is consistent

  1. 5p + 2q +r = 0
  2. 5p – 2q + r = 0
  3. -5p + 2q + r = 0 
  4. 5p + 2q – r = 0

Answer (Detailed Solution Below)

Option 3 : -5p + 2q + r = 0 

System of Linear Equations Question 3 Detailed Solution

Concept:

Consistency means, the system of equations should have either infinite solutions or unique solution

Explanation:

For Consistent solution, the system of equations should have either infinite solutions or unique solution

 

R→ R2 - 2R1

R→ R3 – R1

 

R→ R3 + 2R2

 

 

For consistency ρ [A/b] = ρ [A]

⇒ -5p + 2q + r = 0 

Hence Option(3) is the correct answer.

System of Linear Equations Question 4:

Consider the following system of equations in three real variables x, y, z.

2x – 3y + 7z = 5

3x + y – 3z = 13

2x + 19y – 47z = 32

The system of equation has

A. No Solution

B. A Unique Solution

C. More than one but finite number of solutions

D. More than two but finite number of solutions

  1. Either A or C is correct
  2. Either B or C is correct
  3. Either C or D is correct
  4. Either B or D is correct 

Answer (Detailed Solution Below)

Option 1 : Either A or C is correct

System of Linear Equations Question 4 Detailed Solution

Explanation:

Augmented matrix will be

R3 → R3 – R1

R2 → 2R2 – 3R1

R3 → R3 – 2R2

Rank of A ≠ Rank of Augmented matrix.

Hence given system of equations has no solution.

Hence Option(1) is the correct answer.

System of Linear Equations Question 5:

For what value of k, the equations

x + 4y + z = a,

2x - 3y – 1z = – 3, and

5x – 13y + k z = 9

will not have a unique solution?

  1. -4
  2. 4
  3. 3
  4. -3

Answer (Detailed Solution Below)

Option 1 : -4

System of Linear Equations Question 5 Detailed Solution

Given:

x + 4y + z = a,

2x - 3y – z = – 3, and

5x – 13y + k z = 9

Concept Used:

The given system of equation will not have unique solution if determinant of the coefficient of x, y, and z is equal to zero.

Solution:

D =   = 0

⇒ (-3k - 13) - (4) (2k + 5) +  (- 26 + 15) = 0

⇒ -3k - 13 - 8k - 20  - 11 = 0

⇒ -11k - 44 = 0

⇒ k = -4

 Option 1 is correct.

Top System of Linear Equations MCQ Objective Questions

System of Linear Equations Question 6:

For what value of k, the equations

x + 4y + z = a,

2x - 3y – 1z = – 3, and

5x – 13y + k z = 9

will not have a unique solution?

  1. -4
  2. 4
  3. 3
  4. -3

Answer (Detailed Solution Below)

Option 1 : -4

System of Linear Equations Question 6 Detailed Solution

Given:

x + 4y + z = a,

2x - 3y – z = – 3, and

5x – 13y + k z = 9

Concept Used:

The given system of equation will not have unique solution if determinant of the coefficient of x, y, and z is equal to zero.

Solution:

D =   = 0

⇒ (-3k - 13) - (4) (2k + 5) +  (- 26 + 15) = 0

⇒ -3k - 13 - 8k - 20  - 11 = 0

⇒ -11k - 44 = 0

⇒ k = -4

 Option 1 is correct.

System of Linear Equations Question 7:

What will be the conditions on p, q, r so that the linear system of equations

x + 2y – 3z = p

2x + 6y – 11z = q

x – 2y + 7z = r

is consistent

  1. 5p + 2q +r = 0
  2. 5p – 2q + r = 0
  3. -5p + 2q + r = 0 
  4. 5p + 2q – r = 0

Answer (Detailed Solution Below)

Option 3 : -5p + 2q + r = 0 

System of Linear Equations Question 7 Detailed Solution

Concept:

Consistency means, the system of equations should have either infinite solutions or unique solution

Explanation:

For Consistent solution, the system of equations should have either infinite solutions or unique solution

 

R→ R2 - 2R1

R→ R3 – R1

 

R→ R3 + 2R2

 

 

For consistency ρ [A/b] = ρ [A]

⇒ -5p + 2q + r = 0 

Hence Option(3) is the correct answer.

System of Linear Equations Question 8:

Consider the following system of equations in three real variables x, y, z.

2x – 3y + 7z = 5

3x + y – 3z = 13

2x + 19y – 47z = 32

The system of equation has

A. No Solution

B. A Unique Solution

C. More than one but finite number of solutions

D. More than two but finite number of solutions

  1. Either A or D is correct
  2. Either B or C is correct
  3. Either C or D is correct
  4. Either B or D is correct 
  5. Either A or C is correct 

Answer (Detailed Solution Below)

Option 5 : Either A or C is correct 

System of Linear Equations Question 8 Detailed Solution

Explanation:

Augmented matrix will be

R3 → R3 – R1

R2 → 2R2 – 3R1

R3 → R3 – 2R2

Rank of A ≠ Rank of Augmented matrix.

Hence given system of equations has no solution.

Hence Option(5) is the correct answer.

System of Linear Equations Question 9:

Consider the following system of linear equations

x + y + 5z = 3, x + 2y + mz = 5 and x + 2y + 4z = k.

The system is consistent if 

  1. m ≠ 4
  2. k ≠ 5
  3. m = 4
  4. k = 5

Answer (Detailed Solution Below)

Option :

System of Linear Equations Question 9 Detailed Solution

Explanation:

Consider the augmented matrix  

  

Applying  row operations: 
 

  

  

  

The system is consistent if and only if  

If    , then    for any value of k 

Hence, option (1) is true

If k = 5 , then    for any value of m

Hence, option (4) is true.  

If    and m = 4 , then \rho(A) = 2 \) ,   

and the system will be inconsistent.  

Hence, options (1) and (4) are  correct.

System of Linear Equations Question 10:

Consider the following system of equations in three real variables x, y, z.

2x – 3y + 7z = 5

3x + y – 3z = 13

2x + 19y – 47z = 32

The system of equation has

A. No Solution

B. A Unique Solution

C. More than one but finite number of solutions

D. More than two but finite number of solutions

  1. Either A or C is correct
  2. Either B or C is correct
  3. Either C or D is correct
  4. Either B or D is correct 

Answer (Detailed Solution Below)

Option 1 : Either A or C is correct

System of Linear Equations Question 10 Detailed Solution

Explanation:

Augmented matrix will be

R3 → R3 – R1

R2 → 2R2 – 3R1

R3 → R3 – 2R2

Rank of A ≠ Rank of Augmented matrix.

Hence given system of equations has no solution.

Hence Option(1) is the correct answer.

System of Linear Equations Question 11:

Consider the following system of linear equations x + y + 5z = 3, x + 2y + mz = 5 and x + 2y + 4z = k. The system is consistent if

(A). m ≠ 4

(B). k ≠ 5, m = 4

(C). m = 4, k = 1

(D). m=  4, k = 5

Choose the correct answer from the options given below:

  1. (A), (B) only.
  2. (A) (D) only.
  3. (B), (C) only.
  4. (C) only.

Answer (Detailed Solution Below)

Option 2 : (A) (D) only.

System of Linear Equations Question 11 Detailed Solution

Explanation:

A system of linear equations is considered consistent if it has at least one solution.

Augmented Matrix:

   

Row Operation:

  

   

This gives us:

   

  

  

For the system to be consistent, the last row must not represent an inconsistent equation 

If -m + 4 ≠ 0 (i.e., m ≠ 4), then we can solve for z in the last row and back-substitute to find x and y

If -m + 4 = 0 and k - 5 = 0 (i.e., m = 4 and k = 5), then the last row becomes 0 = 0, which is always true

The system has infinitely many solutions

If -m + 4 = 0 and k - 5 ≠ 0 (i.e., m = 4 and k ≠ 5),

then the last row represents an inconsistent equation (0 = a non-zero value), and the system has no solutions

Therefore, the system is consistent if:

1. m ≠ 4 

2. m = 4 and k = 5

⇒ the correct options are (A) and (D)

Hence Option(2) is the correct answer.

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