Transfer Function MCQ Quiz - Objective Question with Answer for Transfer Function - Download Free PDF

Last updated on Jun 26, 2025

Latest Transfer Function MCQ Objective Questions

Transfer Function Question 1:

The transfer function H(s) of the given circuit is:

Answer (Detailed Solution Below)

Option 2 :

Transfer Function Question 1 Detailed Solution

Explanation:

Transfer Function Analysis of the Given Circuit:

The transfer function H(s) of an electrical circuit represents the relationship between the input and output signals in the Laplace domain. It is expressed as a ratio of the Laplace transform of the output signal to the Laplace transform of the input signal. In this problem, we aim to determine the correct transfer function of the given circuit.

Correct Option:

The correct transfer function is:

Option 2: H(s)=Rs2LRC+sL+R" id="MathJax-Element-32-Frame" role="presentation" style="position: relative;" tabindex="0">H(s)=Rs2LRC+sL+RH(s)=Rs2LRC+sL+R

Derivation:

To derive the transfer function, we analyze the circuit using fundamental principles such as Kirchhoff's Voltage Law (KVL) and Laplace transform techniques.

Step 1: Circuit Configuration and Parameters

The circuit under consideration is likely an RLC circuit, comprising a resistor (R), inductor (L), and capacitor (C). The configuration of the circuit determines how these components interact, influencing the transfer function. Based on the mathematical representation in the options, we assume it is a series RLC circuit.

Step 2: Applying Kirchhoff's Voltage Law (KVL)

For a series RLC circuit, KVL states that the sum of voltage drops across the resistor, inductor, and capacitor equals the applied input voltage:

Vin(t)=VR(t)+VL(t)+VC(t)" id="MathJax-Element-33-Frame" role="presentation" style="position: relative;" tabindex="0">Vin(t)=VR(t)+VL(t)+VC(t)Vin(t)=VR(t)+VL(t)+VC(t)

Using the Laplace transform, the voltage drops can be expressed as:

  • VR(s)=RI(s)" id="MathJax-Element-34-Frame" role="presentation" style="position: relative;" tabindex="0">VR(s)=RI(s)VR(s)=RI(s)
  • VL(s)=sLI(s)" id="MathJax-Element-35-Frame" role="presentation" style="position: relative;" tabindex="0">VL(s)=sLI(s)VL(s)=sLI(s)
  • VC(s)=I(s)sC" id="MathJax-Element-36-Frame" role="presentation" style="position: relative;" tabindex="0">VC(s)=I(s)sCVC(s)=I(s)sC

Substituting these into the KVL equation:

Vin(s)=RI(s)+sLI(s)+I(s)sC" id="MathJax-Element-37-Frame" role="presentation" style="position: relative;" tabindex="0">Vin(s)=RI(s)+sLI(s)+I(s)sCVin(s)=RI(s)+sLI(s)+I(s)sC

Factorizing I(s)" id="MathJax-Element-38-Frame" role="presentation" style="position: relative;" tabindex="0">I(s)I(s) :

Vin(s)=I(s)(R+sL+1sC)" id="MathJax-Element-39-Frame" role="presentation" style="position: relative;" tabindex="0">Vin(s)=I(s)(R+sL+1sC)Vin(s)=I(s)(R+sL+1sC)

I(s)=Vin(s)R+sL+1sC" id="MathJax-Element-40-Frame" role="presentation" style="position: relative;" tabindex="0">I(s)=Vin(s)R+sL+1sCI(s)=Vin(s)R+sL+1sC

Step 3: Output Voltage Relation

The output voltage is typically taken across one of the components. Based on the options provided, the output voltage is likely across the resistor. Therefore:

Vout(s)=VR(s)=RI(s)" id="MathJax-Element-41-Frame" role="presentation" style="position: relative;" tabindex="0">Vout(s)=VR(s)=RI(s)Vout(s)=VR(s)=RI(s)

Substituting I(s)" id="MathJax-Element-42-Frame" role="presentation" style="position: relative;" tabindex="0">I(s)I(s) into Vout(s)" id="MathJax-Element-43-Frame" role="presentation" style="position: relative;" tabindex="0">Vout(s)Vout(s) :

Vout(s)=RVin(s)R+sL+1sC" id="MathJax-Element-44-Frame" role="presentation" style="position: relative;" tabindex="0">Vout(s)=RVin(s)R+sL+1sCVout(s)=R⋅Vin(s)R+sL+1sC

Thus, the transfer function H(s)" id="MathJax-Element-45-Frame" role="presentation" style="position: relative;" tabindex="0">H(s)H(s) becomes:

H(s)=Vout(s)Vin(s)=RR+sL+1sC" id="MathJax-Element-46-Frame" role="presentation" style="position: relative;" tabindex="0">H(s)=Vout(s)Vin(s)=RR+sL+1sCH(s)=Vout(s)Vin(s)=RR+sL+1sC

Simplify the denominator:

H(s)=Rs2LRC+sL+R" id="MathJax-Element-47-Frame" role="presentation" style="position: relative;" tabindex="0">H(s)=Rs2LRC+sL+RH(s)=Rs2LRC+sL+R

This matches Option 2, confirming its correctness.

Important Information:

To further analyze the other options, let’s evaluate their mathematical expressions:

Option 1: H(s)=Cs2L+sLRC+R" id="MathJax-Element-48-Frame" role="presentation" style="position: relative;" tabindex="0">H(s)=Cs2L+sLRC+RH(s)=Cs2L+sLRC+R

This option incorrectly places C" id="MathJax-Element-49-Frame" role="presentation" style="position: relative;" tabindex="0">CC in the numerator instead of R" id="MathJax-Element-50-Frame" role="presentation" style="position: relative;" tabindex="0">RR . Moreover, the denominator does not match the standard form derived from the circuit analysis. Therefore, it is incorrect.

Option 3: H(s)=Rs2L+sLRC+R" id="MathJax-Element-51-Frame" role="presentation" style="position: relative;" tabindex="0">H(s)=Rs2L+sLRC+RH(s)=Rs2L+sLRC+R

Although this option has R" id="MathJax-Element-52-Frame" role="presentation" style="position: relative;" tabindex="0">RR in the numerator, the denominator differs from the correct one derived earlier. Specifically, it omits the term s2LRC" id="MathJax-Element-53-Frame" role="presentation" style="position: relative;" tabindex="0">s2LRCs2LRC , making it inconsistent with the circuit's transfer function.

Option 4: H(s)=Cs2LRC+sL+R" id="MathJax-Element-54-Frame" role="presentation" style="position: relative;" tabindex="0">H(s)=Cs2LRC+sL+RH(s)=Cs2LRC+sL+R

This option swaps R" id="MathJax-Element-55-Frame" role="presentation" style="position: relative;" tabindex="0">RR for C" id="MathJax-Element-56-Frame" role="presentation" style="position: relative;" tabindex="0">CC in the numerator. However, the denominator matches the correct transfer function. Since the numerator should be R" id="MathJax-Element-57-Frame" role="presentation" style="position: relative;" tabindex="0">RR , this option is incorrect.

Conclusion:

The correct transfer function for the given circuit is H(s)=Rs2LRC+sL+R" id="MathJax-Element-58-Frame" role="presentation" style="position: relative;" tabindex="0">H(s)=Rs2LRC+sL+RH(s)=Rs2LRC+sL+R , corresponding to Option 2. This result is obtained through a systematic application of circuit analysis principles, including KVL and Laplace transform techniques.

Transfer Function Question 2:

Two systems S1 and S2 are connected in cascade and S1 is described as  and S2 is an RC high pass filter with a time constant of τ = 1 sec. If the input of S1 is x(t) = e-2t u(t). The output of the cascaded system is

  1. –te-t u(t)
  2. te-t u(t)
  3. δ(t) – e-t u(t)
  4. δ(t) + e-t u(t)
  5. None of these

Answer (Detailed Solution Below)

Option 3 : δ(t) – e-t u(t)

Transfer Function Question 2 Detailed Solution

System 1:

 

By applying the Laplace transform,

Y(s) = s x(s) + 2 x(s)

 

⇒ H1(s) = s + 2

System 2:

The transfer function of high pass filter is,

 

τ = RC = 1 sec

 

Both the systems are connected in cascade connection.

H(s) = H1(s) H2(s)

 

 

x(t) = e-2t

 

 

 

⇒ y(t) = δ(t) – e-t u(t)

Transfer Function Question 3:

The input 𝑥(𝑡) to a system is related to its output 𝑦(𝑡) as  

Here 𝑢(𝑡) represents a unit-step function.

The transfer function of this system is ________ 

Answer (Detailed Solution Below)

Option 2 :

Transfer Function Question 3 Detailed Solution

Calculation

The transfer function is defined as the ratio of the Laplace transform of output to the Laplace transform of the input keeping initial conditions zero.

Given, 

where, y(t) = Output

x(t) = Input

Taking Laplace on both sides:

Transfer Function Question 4:

The roots of a system having a transfer function  will be:

  1. either ‐3 or ‐4
  2. either ‐3 or 4
  3. either 3 or ‐4
  4. either 3 or 4

Answer (Detailed Solution Below)

Option 1 : either ‐3 or ‐4

Transfer Function Question 4 Detailed Solution

Concept:-

The transistor function is given by = 

Where K = dc gain Z1, Z2,--- = zeros

P1, P2, --- = Pole location

Calculation:

The roots of the transfer function is -3, -4. 

Transfer Function Question 5:

The unique model of a system is

  1. Block diagrams
  2. State variables
  3. Signal flow graphs
  4. Transfer function

Answer (Detailed Solution Below)

Option 4 : Transfer function

Transfer Function Question 5 Detailed Solution

Transfer Function:

  • The transfer function of a system is defined as the ratio of the Laplace transform of output to the Laplace transform of input where all the initial conditions are zero.
  • The transfer function for the system is unique & it is applicable only for linear time-invariant (LTI) systems.

Signal flow graphs:

  • Signal flow graphs are used to find the transfer function of the control system by converting the block diagrams into signal flow graphs
  • It cannot be used for nonlinear systems.

Block diagrams:

  • A block diagram is used to represent a control system in diagram form.
  • Each element of the control system is represented with a block and the block is the symbolic representation of the transfer function of that element.

State variables:

  • A state variable is one of the sets of variables that are used to describe the mathematical "state" of a dynamical system.
  • The state variable method is used for analysis of time-variant systems.

Top Transfer Function MCQ Objective Questions

The impulse response of the transfer function 1 is

  1. an impulse function
  2. a step function
  3. a pulse function
  4. Cannot be determined

Answer (Detailed Solution Below)

Option 1 : an impulse function

Transfer Function Question 6 Detailed Solution

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Concept:

  • The impulse response of any system is known as the transfer function.
  • The transfer function is defined as the ratio of the Laplace transform of the output to the Laplace transform of the input by assuming initial conditions to be zero.

Explanation:

T.F. = 

T.F. =  

Taking Inverse Laplace on both sides:

A unity feedback control system has 

The order and type of the closed-loop system will be:

  1. 3 and 3
  2. 2 and 3
  3. 1 and 3
  4. 3 and 2

Answer (Detailed Solution Below)

Option 4 : 3 and 2

Transfer Function Question 7 Detailed Solution

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Concept:

Poles of closed-loop system = zeroes of the characteristic equation.

Characteristic equation is given by:

1 + G(s) H(s) = 0

Order: Highest power of characteristic equation.

Type: It is obtained by observing the number of open loop poles occuring at origin.

Analysis:

H(s) = 1

The characteristic equation will be:

s2 (sT + 1) + k = 0

s3 T + s2 + k = 0

The highest power of the above characteristic equation is 3

So, order = 3

Type = 2

Consider a system with the closed loop transfer function  with input R(s) and output C(s). When all initial conditions are zero and the input is an impulse then the output c(t) is:

  1. e-8t + 10 e-t
  2. 10 e-3t - 10 e-5t
  3. 10 e-3t + 10 e-5t
  4. 20 e-8t + 5 e-15t

Answer (Detailed Solution Below)

Option 3 : 10 e-3t + 10 e-5t

Transfer Function Question 8 Detailed Solution

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Concept:

Consider a second-order control system with unity feedback: 

Closed-loop transfer function is given by

 where,

C(s) = Output response of CLTF

R(s) = Input to the system

ωn = Undamped natural frequency in rad/sec

ζ = Damping ratio

Application:

Given:

Input R(t) = δ(t) implies R(s) = 1,

Closed Loop Transfer function  

Substitute R(s) = 1 in above CLTF, We get

Taking Inverse Laplace Transform on both sides,

C(t) = 10 e-3t u(t) + 10 e-5t u(t)

C(t) = 10 (e-3t + e-5t) u(t)

The impulse response of a system described by the differential equation  will be

  1. a constant
  2. an impulse function
  3. a sinusoid
  4. an exponentially decaying function

Answer (Detailed Solution Below)

Option 3 : a sinusoid

Transfer Function Question 9 Detailed Solution

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Concept:

A transfer function is defined as the ratio of the Laplace transform of the output to the Laplace transform of the input by assuming initial conditions are zero.

TF = L[output]/L[input]

For unit impulse input i.e. r(t) = δ(t)

⇒ R(s) = δ(s) = 1

Now transfer function = C(s)

Therefore, the transfer function is also known as the impulse response of the system.

Transfer function = L[IR]

IR = L-1 [TF]

Calculation:

By aplying the Laplace transform,

s2 Y(s) + Y(s) = X(s)

Impulse response will be the inverse Laplace transform of the above transfer function.

By applying the inverse Laplace transform,

⇒ y(t) = sin t

Therefore, the impusle response of the gien system is a sinusoid.

A linear system with H(s) = 1/s is excited by a unit step function input. The output for t > 0 is given by

  1. δ(t)
  2. 1
  3. t
  4. t2

Answer (Detailed Solution Below)

Option 3 : t

Transfer Function Question 10 Detailed Solution

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Concept:

A transfer function is defined as the ratio of Laplace transform of the output to the Laplace transform of the input by assuming initial conditions are zero.

TF = L[output] / L[input]

So that transfer function of the system is used to calculate the output for a given input.

For unit impulse input i.e. r(t) = δ(t)

⇒ R(s) = δ(s) = 1

Now transfer function = C(s)

Therefore, transfer function is also known as impulse response of the system.

Transfer function = L[IR]

IR = L-1 [TF]

Application:

Given-

TF = H(s) = 1/s,

Input is unit step, R(s) = 1/s

Now output for t > 0 can be calculated as

C(s) = H(s) x R(s)

C(s) = (1/s) x (1/s)

C(s) = 1 / s2

L-1[C(s)] = t

C(t) = t = ramp function

A function y(t) satisfies the following differential equation:

Where δ(t) is unit impulse function and u(t) is unit step function. Assuming zero initial conditions, what is y(t)?

  1. et
  2. e-t
  3. et u(t)
  4. e-t u(t)

Answer (Detailed Solution Below)

Option 4 : e-t u(t)

Transfer Function Question 11 Detailed Solution

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Concept:

A transfer function is defined as the ratio of Laplace transform of the output to the Laplace transform of the input by assuming initial conditions are zero.

TF = L[output]/L[input]

For unit impulse input i.e. r(t) = δ(t)

⇒ R(s) = δ(s) = 1

Now transfer function = C(s)

Therefore, the transfer function is also known as the impulse response of the system.

Transfer function = L[IR]

IR = L-1 [TF]

Calculation:

Given differential equation is,

sY(s) + Y(s) = 1

y(t) = e-t u(t)

For the closed-loop system shown, the transfer function  is

Answer (Detailed Solution Below)

Option 2 :

Transfer Function Question 12 Detailed Solution

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Given:

Forward path gain = G

Feedback path gain = H

Input signal = R(s)

Output signal = C(s)

Error signal = E(s)

C(s) = G × E(s)

Error signal = Input signal - Feedback signal

E(s) = R(s) - H × C(s)

E(s) = R(s) - H × G × E(s)

E(s) + H × G × E(s) = R(s) 

E(s) [1 + GH] = R(s)

Find the overall transfer function for the following system.

Answer (Detailed Solution Below)

Option 2 :

Transfer Function Question 13 Detailed Solution

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By using the block-reduction technique:

Step 1:

Blocks having value 2 and  are in parallel.

Step 2:

Blocks having value  and  are cascaded.

Step 3:

Noe its a negative UFB system:

The transfer function of a system is given by,

Let the output of the system be  for the input, . Then the minimum and maximum values of ϕ (in radians) are respectively

Answer (Detailed Solution Below)

Option 4 :

Transfer Function Question 14 Detailed Solution

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Transfer function,

Vi (t) = Vm sin(ωt)

Vo (t) = Vm sin(ωt + ϕ)

Here, ϕ = tan-1 (-ω) - tan-1(ω)

= - tan1(ω) - tan-1 (ω)

= - 2 tan-1(ω)

At ω = 0, 

⇒ ϕ = - 2 tan-1(0) = 0 (since tan-1(0) = 0 )

At ω = ∞,

⇒ - 2 tan-1(∞) = - 2 × π/2 = - π (since tan-1(∞) = π/2)

Range of ϕ = (-π, 0)

The unique model of a system is

  1. Block diagrams
  2. State variables
  3. Signal flow graphs
  4. Transfer function

Answer (Detailed Solution Below)

Option 4 : Transfer function

Transfer Function Question 15 Detailed Solution

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Transfer Function:

  • The transfer function of a system is defined as the ratio of the Laplace transform of output to the Laplace transform of input where all the initial conditions are zero.
  • The transfer function for the system is unique & it is applicable only for linear time-invariant (LTI) systems.

Signal flow graphs:

  • Signal flow graphs are used to find the transfer function of the control system by converting the block diagrams into signal flow graphs
  • It cannot be used for nonlinear systems.

Block diagrams:

  • A block diagram is used to represent a control system in diagram form.
  • Each element of the control system is represented with a block and the block is the symbolic representation of the transfer function of that element.

State variables:

  • A state variable is one of the sets of variables that are used to describe the mathematical "state" of a dynamical system.
  • The state variable method is used for analysis of time-variant systems.

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