Question
Download Solution PDFA and B together can complete a certain work in 20 days whereas B and C together can complete it in 24 days. If A is twice as good a workman as C, then in what time will B alone do 40% of the same work?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A = 2C
A + B in 20 days
B + C in 24 days
Concept used:
Total work = LCM of time taken by the workers
Calculation:
LCM of 20 and 24 is 120
So, efficiency of A and B = 120/20 = 6 and efficiency of B and C = 120/24 = 5
Now 2C + B = 6 and B + C = 5
So, C = 1
B = 4
40% of the work = 120 × 2/5 = 48 units
So, B will take 48/4 = 12 days
∴ B alone do 40% of the same work in 12 days
Shortcut Trick
Now 2C + B = 6 and B + C = 5
So, C = 1
B = 4
So,
A, B and C = 2, 4, and 1
40% of the work = 120 × 2/5 = 48 units
So, B will take 48/4 = 12 days
Last updated on Jul 12, 2025
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