Question
Download Solution PDFA pure inductor of 70 mH is connected to a source of AC voltage. If the frequency of the source is 50 Hz, then find the inductive reactance.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Inductive reactance:
- The inductive reactance is the opposition offered by the inductor in an AC circuit to the flow of ac current.
- Its SI unit is Ohm(Ω).
- The inductive reactance is given as,
⇒ XL = 2πfL
Where f = frequency of ac current and L = self-inductance of the coil
Impedance:
- Impedance is essentially everything that obstructs the flow of electrons within an electrical circuit.
- For a pure inductor, the inductive reactance is equal to the impedance.
AC voltage applied to an inductor:
- When an AC voltage is applied to an inductor, the current in the circuit is given as,
- In a pure inductor circuit, the current reaches its maximum value later than the voltage by one-fourth of a period.
CALCULATION:
Given L = 70 mH = 70×10-3 H, and f = 50 Hz
- We know that the inductive reactance is given as,
⇒ XL = 2πfL
⇒ XL = 22 Ω
- Hence option 1 is correct.
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