চারটি সংখ্যা-জোড়া দেওয়া হয়েছে, যার মধ্যে তিনটি কোনো না কোনোভাবে একই রকম এবং একটি ভিন্ন। ভিন্ন সংখ্যা-জোড়াটি বেছে নিন।

This question was previously asked in
SSC CGL 2020 Tier-I Official Paper 4 (Held On : 16 Aug 2021 Shift 1)
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  1. 21 ∶ 139
  2. 25 ∶ 167
  3. 15 ∶ 197
  4. 27 ∶ 181

Answer (Detailed Solution Below)

Option 3 : 15 ∶ 197
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Detailed Solution

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যুক্তিটি হল:

1ম সংখ্যা × 7 - 8 = দ্বিতীয় সংখ্যা

1. 21 ∶ 139 → 21 × 7 - 8 = 147 - 8 = 139

2. 25 : 167 → 25 × 7 - 8 = 175 - 8 = 167

3. 15 : 197 → 15 × 7 - 8 = 105 - 8 = 97 ≠ 197

4. 27 : 181 → 27 × 7 - 8 = 189 - 8 = 181

বিকল্প 3 ব্যতীত, সমস্ত বিকল্প প্রদত্ত যুক্তি অনুসরণ করে। এইভাবে বিকল্প 3 এদের মধ্যে বেমানান।

তাই, '15 : 197' হল বেমানান।

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