Question
Download Solution PDFFor a BG track with M+5 sleeper density, find the number of fish plates required for 1 km of track.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Given data:
Density of sleeper = M+5
For BG track length of one rail (\(l\)) = 13 m
Length of track (L) = 1 km or 1000 m
The number of fish plates required (N) =?
Number of rails required for 1 km of track (n) = \({Length\, of\, track(L)\over One\, rail\, length\,(l)}\)
Number of rails required for 1 km of track (n) = \({1000\over 13}=76.92 \approx77\)
Number of rails required for 1 km of track (n) = 77
Number of joints on both sides of the track (n'') = 2 × Number of rails required for the track (n)
Number of joints on both sides of the track (n'') = 2 × 77 = 154
Number of joints on both sides of the track (n'') = 154
Number of fish plates required for a given track (N) = 2 × Number of joints on track (n'')
Number of fish plates required for given track (N) = 2 × 154 = 308
Number of fish plates required for given track (N) = 308
Important Points
There are two fish plates and four bolts and four nuts required at one joint.
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