Question
Download Solution PDFएक JFET में निम्नलिखित पैरामीटर हैं: IDSS = 30 mA, VGS(off) = - 5V, VGS = -4.5 V। अपवाह धारा का मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
JFET में संकुचन या संतृप्ति क्षेत्र में, अपवाह धारा शॉक्ले समीकरण द्वारा दिया जाता है और इसे इस प्रकार लिखा जाता है
\({I_D} = {I_{DSS}}{\left( {1 - \frac{{{V_{GS}}}}{{{V_{GS\left( {off} \right)}}}}} \right)^2}\)
गणना:
दिया गया है IDSS = 30 mA
VGS = -4.5 वोल्ट
VGS(off) = -5 वोल्ट
\({I_D} = 30{\left( {1 - \frac{{ - 4.5}}{{ - 5}}} \right)^2} = 0.3\;mA\)
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