एक JFET में निम्नलिखित पैरामीटर हैं: IDSS = 30 mA, VGS(off) = - 5V, VGS = -4.5 V। अपवाह धारा का मान ज्ञात कीजिए।

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SSC JE Electrical 10 Oct 2023 Shift 2 Official Paper-I
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  1. 30 mA
  2. 0.5 mA
  3. 15 mA
  4. 0.3 mA

Answer (Detailed Solution Below)

Option 4 : 0.3 mA
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संकल्पना:

JFET में संकुचन या संतृप्ति क्षेत्र में, अपवाह धारा शॉक्ले समीकरण द्वारा दिया जाता है और इसे इस प्रकार लिखा जाता है

\({I_D} = {I_{DSS}}{\left( {1 - \frac{{{V_{GS}}}}{{{V_{GS\left( {off} \right)}}}}} \right)^2}\)

गणना:

दिया गया है IDSS = 30 mA

VGS = -4.5 वोल्ट

VGS(off) = -5 वोल्ट

\({I_D} = 30{\left( {1 - \frac{{ - 4.5}}{{ - 5}}} \right)^2} = 0.3\;mA\)

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