Question
Download Solution PDFसदिश n = 5i + 3j + 8k को x - अक्ष के चारों ओर 90° के एक कोण से घुमाइए। तो घूर्णित सदिश (Hn) क्या होगी?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
X - अक्ष के चारों ओर घूर्णन आव्यूह निम्न द्वारा ज्ञात किया जाता है
R(x, θ) =
गणना:
R(x, 90°) =
R(x, 90°) =
अब, सदिश n = 5i + 3j + 8k के चारों ओर घुमाने पर
=
=
=
Last updated on Jul 2, 2025
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