In a given score distribution of 12, 14, 16, 18 and 20 , the sum of square deviation is:

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UGC NET (Education) Official Paper-II (Held On: 14 Mar, 2023 Shift 2)
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  1. 12
  2. 24
  3. 40
  4. Zero

Answer (Detailed Solution Below)

Option 3 : 40
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UGC NET Paper 1: Held on 21st August 2024 Shift 1
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Detailed Solution

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Key Points The sum of square deviation is calculated by taking the square of the difference between each score and the mean and then adding all of the squares together.

The mean of the scores 12, 14, 16, 18, and 20 is 16.

The square of the difference between each score and the mean is:

  • (12 - 16)^2 = 16
  • (14 - 16)^2 = 4
  • (16 - 16)^2 = 0
  • (18 - 16)^2 = 4
  • (20 - 16)^2 = 16

The sum of these squares is 40.

Therefore, the sum of the square deviation for the given score distribution is 40.

Here is the solution in mathematical form:

Sum of square deviation = Σ(x - μ)^2

Where:

  • x is a score
  • μ is the mean
  • Σ is the sum

In this case, the sum of the square deviation is:

Sum of square deviation = Σ(12 - 16)^2 + (14 - 16)^2 + (16 - 16)^2 + (18 - 16)^2 + (20 - 16)^2
= 16 + 4 + 0 + 4 + 16
= 40
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