The formula for rms value of sinusoidal signal in terms of peak to peak voltage, Vp-p is _______.

This question was previously asked in
SSC JE Electrical 14 Nov 2022 Shift 3 Official Paper
View all SSC JE EE Papers >
  1. \(\rm \frac{V_{p-p}}{\sqrt2}\)
  2. \(\rm \frac{V_{p-p}}{2\sqrt2}\)
  3. \(\rm \frac{V_{p-p}}{2}\)
  4. \(\rm \frac{V_{p-p}}{\pi\sqrt2}\)

Answer (Detailed Solution Below)

Option 2 : \(\rm \frac{V_{p-p}}{2\sqrt2}\)
Free
Electrical Machine for All AE/JE EE Exams Mock Test
7.7 K Users
20 Questions 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Concept

Any sinusoidal signal is represented as:

F1 Vinanti Engineering 26.12.22 D6

The peak-to-peak value is given by:

Vp-p = 2Vm

\(V_m={V_{p-p}\over 2}\)

where, Vpp = Peak-to-peak value

Vm = Maximum value

Calculation

The RMS value is given by:

\(V_{RMS}={V_m\over \sqrt{2}}\)

\(V_{RMS}={V_{p-p}\over 2\sqrt{2}}\)

Latest SSC JE EE Updates

Last updated on Jul 1, 2025

-> SSC JE Electrical 2025 Notification is released on June 30 for the post of Junior Engineer Electrical, Civil & Mechanical.

-> There are a total 1340 No of vacancies have been announced. Categtory wise vacancy distribution will be announced later.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

Get Free Access Now
Hot Links: teen patti go teen patti master gold teen patti star teen patti master golden india