The initial tension T0 of the belt is equal to-

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RSMSSB JE Electrical/Mechanical 2020 Official Paper (Diploma): Held on 26 Dec 2020
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  1. Tension in the tight side of the belt
  2. Tension in the slack side of the belt
  3. Sum of the tensions in the tight and slack side of the belt
  4. Average tension of the tight side and slack side of the belt

Answer (Detailed Solution Below)

Option 4 : Average tension of the tight side and slack side of the belt
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Detailed Solution

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Explanation:

Initial tension (To):

When a belt is first fitted to a pair of pulleys, an initial tension To is given to the belt when the system is stationary. When transmitting power, the tension on the tight side increases to T1 and that on the slack side decreases to T2.

It is assumed that the material of the belt is perfectly elastic, i.e. the strain in the belt is proportional to the stress in it and the total length of the belt remains unchanged. Therefore, the tension on the tight side will increase by the same amount as the tension on the slack side decreases.

Tension on tight side T1 = To + δT

Tension on slack side T2 = To - δT

where To is the initial tension and T1 and T2 is the tension on the tight and slack side respectively.

Mathematically initial tension is

\(T_o= \frac{{T_1 + T_2 }}{2}\)

 Considering centrifugal tension:

\(T_o= \frac{{T_1 + T_2 +2T_c }}{2}\)

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