Question
Download Solution PDFThe instantaneous value of current flowing in a circuit is expressed as i = 8 sin ωt + 6 sin 2ωt. If this current flows through a resistance of 10 Ω, what will be the power dissipated?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The power dissipated across a resistor is given by:
If a current is represented as i = i1 sin ωt + i2 sin 2ωt, then rms value is given by:
Calculation
Given, R = 10 Ω
i = 8 sin ωt + 6 sin 2ωt
P = 500 W
Last updated on May 29, 2025
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