The number of 4 digit numbers without repetition that can be formed using the digits 1, 2, 3, 4, 5, 6, 7 in which each number has two odd digits and two even digits is

  1. 432
  2. 436
  3. 450
  4. 454

Answer (Detailed Solution Below)

Option 1 : 432
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Detailed Solution

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Concept:

Product rule:

If we can select object A in m ways and object B in n ways then we can select the object A and B in mn ways.

 

Calculation:

We have to form 4 digit numbers so we can do it in 4! ways.

There are 4 odd numbers and we have to select 2 odd numbers out of those which can be done in  ways.

We will calculate this as follows:

Similarly, there are 3 even numbers and we have to select 2 out of those which can be done in  ways.

Which is same as:

Therefore, using the product rule we can calculate the required number of formations as follows:

The number of 4 digit numbers without repetition that can be formed using the digits 1, 2, 3, 4, 5, 6, 7 in which each number has two odd digits and two even digits is 432.

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