What is the output of the following program?

#include <stdio.h >

# define SQR(x) (x*x)

int main()

{ int a, b = 3;

a=SQR(b+2);

printf("%d",a);

return 0;

}

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Question

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What is the output of the following program?

#include <stdio.h >

# define SQR(x) (x*x)

int main()

{ int a, b = 3;

a=SQR(b+2);

printf("%d",a);

return 0;

}

This question was previously asked in

UGC NET Computer Science (Paper 2) 07 Dec 2023 Official Paper

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25
11
Garbage value
24

Answer 1

The correct answer is 11

EXPLANATION:

The code defines a macro SQR(x) that squares its argument. The macro is defined as (x*x). When SQR(b+2) is evaluated, it becomes (b+2*b+2), not (b+2)*(b+2), because of how the preprocessor substitutes macro definitions.

#include <stdio.h >

# define SQR(x) (x*x)

int main()

{ int a, b = 3;

a=SQR(b+2);

printf("%d",a);

return 0;

}

So, given b=3, (b+2*b+2) will be equal to (3+2*3+2), which equals 11.

Hence, the answer is 2) 11.

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Question

What is the output of the following program?

#include <stdio.h >

# define SQR(x) (x*x)

int main()

{ int a, b = 3;

a=SQR(b+2);

printf("%d",a);

return 0;

}

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Question

What is the output of the following program? #include <stdio.h > # define SQR(x) (x*x) int main() { int a, b = 3; a=SQR(b+2); printf("%d",a); return 0; }

Answer (Detailed Solution Below)

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What is the output of the following program?

#include <stdio.h >

# define SQR(x) (x*x)

int main()

{ int a, b = 3;

a=SQR(b+2);

printf("%d",a);

return 0;

}