Parallel RC Circuit MCQ Quiz in मल्याळम - Objective Question with Answer for Parallel RC Circuit - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക
Last updated on Apr 6, 2025
Latest Parallel RC Circuit MCQ Objective Questions
Top Parallel RC Circuit MCQ Objective Questions
Parallel RC Circuit Question 1:
The circuit shown in the figure is used to charge capacitor C alternately from the current sources as indicated. The switches \({S_1}\) and \({S_2}\) are mechanically coupled and connected as follows?
For \(2nT \le t \le \left( {2n + 1} \right)T\left( {n = 0,1,2 \ldots } \right){S_1}\)to \({P_1}\) and \({S_2}\) to \({P_2}\)
For \(\left( {2n + 1} \right)T \le t \le \left( {2n + 2} \right)T\left( {n = 0,1,2 \ldots } \right){S_1}\)to \({Q_1}\) and \({S_2}\) to \({Q_2}\)
Assume that the capacitor has 0 initial charge. Given that \(u(t)\) is a unit step function, the voltage, \({V_c}\left( t \right)\) across the capacitor is given by
Answer (Detailed Solution Below)
Parallel RC Circuit Question 1 Detailed Solution
\({V_c} = \frac{1}{c}\mathop \smallint \limits_0^t idt\)
& \(C = 1F\)
Then \({V_c} = \mathop \smallint \limits_0^t i\left( t \right)dt\)
Since \(2nT\) to \((2n+1)T\) switch S1 is connected to \({P_1}\) & \({S_2}\) is connected \({P_2}\) therefore capacitor will charge in this period by 1A current source.
Therefore for \(0 < t < T\) →
\({V_c} = \mathop \smallint \limits_0^t 1.dt = t\)
Now,
For \(T < t < 2T\)
\(\begin{array}{l} {V_c} = T - \mathop \smallint \limits_T^t dt = 2T - t\\ \therefore At\ t = T\\ {V_c} = T\\ \&\ At\ t = 2T\\ {V_c} = 2T \end{array}\)
Similarly,
For \(2T < t < 3T\)
\({V_1}\left( t \right) = \mathop \smallint \limits_4^t dt = t - 2T\)
Now, \(at\ t = 3T,{\ V_c} = T\)
& \(at\ t = 2T{\ V_c} = 0\)
∴only option (3) satisfies the above values.
Parallel RC Circuit Question 2:
In the figure shown below, assume that all the capacitors are initially uncharged. If \({V_i}\left( t \right) = 10u\left( t \right)\) voltages, \({V_0}\left( t \right)\) is given by?
Answer (Detailed Solution Below)
Parallel RC Circuit Question 2 Detailed Solution
Since \(\rm {V_1}\left( t \right) = 10u\left( t \right)\) i.e. valid for \(\rm t > 0\)
Since R1C1=R2C2 the circuit acts as pure resistive circuit as shown in below figure,
Therefore by voltage division output voltage, Vo = 8 u(t) V