Question
Download Solution PDFA BJT is configured as a common-base amplifier; which of the following statements is INCORRECT?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept of Common-Base (CB) Configuration:
In a common-base BJT amplifier:
-
Input signal is applied to the emitter
-
Output is taken from the collector
-
Base is common to both input and output (grounded for AC signals)
Additional Information
1) Suitable for high-frequency applications
-
Correct: The CB configuration has excellent high-frequency response due to:
-
Low input impedance
-
No Miller effect (capacitance multiplication)
-
Better bandwidth compared to CE configuration
-
2) Voltage gain is very high
-
Correct: While current gain (α) is slightly less than 1, the CB amplifier provides high voltage gain (comparable to CE).
3) Operates as an amplifier in saturation region
-
Incorrect (Answer):
-
BJT acts as an amplifier only in the active region (where IC = βIB holds).
-
In saturation, the transistor acts as a closed switch (not for amplification).
-
4) Works as an off switch when both junctions are reverse-biased
-
Correct: This describes the cutoff region (transistor acts as an open switch).
Conclusion:
The incorrect statement is Option 3, because a CB amplifier must operate in the active region for proper amplification, not saturation.
Final Answer: 3) The CB configuration operates as an amplifier when the transistor is in the saturation region.
Last updated on Jun 7, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.