Element 'B' forms ccp structure and 'A' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:

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JEE Mains Previous Paper 1 (Held On: 08 Apr 2019 Shift 1)

Answer 1

Concept:

Atom A:

The number of atoms in octahedral void = 4 atoms

Half of the octahedral voids = \(\frac{4}{2} = 2\) atoms

Number of A atoms = 2 atoms

Atom B:

Number of atoms in CCP lattice structure = 4 atoms

Number of B atoms = 4 atoms

Atom Oxygen:

Number of atoms in all tetrahedral voids = 8

Number of oxygen atoms = 8 atoms

Thus, the compound formed is: A₂B₄O₈⇒ AB₂O₄