Given x = 2y + 4 and y = kx + 6 are the lines of regression of x on y and y on x respective.

Find the value of k, if value of r is 0.5.

  1. \(\frac{1}{8}\)
  2. \(\frac{1}{3}\)
  3. \(\frac{1}{2}\)
  4. \(\frac{1}{4}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{1}{8}\)
Free
UPSC NDA 01/2025 General Ability Full (GAT) Full Mock Test
5.8 K Users
150 Questions 600 Marks 150 Mins

Detailed Solution

Download Solution PDF

CONCEPT:

Correlation coefficient is the geometric mean between regression coefficients i.e.\({\rm{r}} = \pm \sqrt {{{\rm{b}}_{{\rm{yx}}}}{{\rm{b}}_{{\rm{xy}}}}} \)

CALCULATIONS:

Given equations are x = 2y + 4 and y = kx + 6.

\({{\rm{b}}_{{\rm{yx}}}} = k\) And \({{\rm{b}}_{{\rm{xy}}}} = 2\)

\({\rm{r}} = \pm \sqrt {{{\rm{b}}_{{\rm{yx}}}}{{\rm{b}}_{{\rm{xy}}}}} \)

\(\frac{1}{2} = \pm \sqrt {{{\rm{b}}_{{\rm{yx}}}} \times 2} \)           (On squaring both sides)

\(2{{\rm{b}}_{{\rm{yx}}}} = \frac{1}{4}\)                      ⇒ \({{\rm{b}}_{{\rm{yx}}}} = \frac{1}{8}\)

∴ \({{\rm{b}}_{{\rm{yx}}}} = k = \frac{1}{8}\)

Latest NDA Updates

Last updated on Jul 8, 2025

->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.

->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

Get Free Access Now
Hot Links: teen patti joy teen patti master official teen patti star teen patti mastar