Question
Download Solution PDFकेंद्र O के एक वृत्त में, AB व्यास है और CD एक जीवा इस प्रकार है कि ABCD एक समलम्ब है। यदि ∠BAC = 25° है, तो ∠CAD का मान कितना है∶
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है, ∠BAC = 25°
⇒ ∠ACB = 90° [अर्धवृत्त में कोण 90 होता है]
ΔACB में
⇒ ∠ACB + ∠CBA + ∠BAC = 180°
⇒ ∠CBA = 180° – 90° – 25° = 65°
⇒ ∠DCA = ∠CAB = 25° [अन्य आंतरिक कोण]
⇒ ∠DCA = ∠ABD = 25°and ∠CAD = ∠DBC
∵ एक ही चाप बनाने या दो समान चाप बनाने वाले दो उत्कीर्ण कोण समान होते हैं।
⇒ ∠CBA = ∠DBC + ∠ABD
⇒ 65° = ∠DBC + 25°
⇒ ∠DBC = 65° – 25° = 40°
⇒ ∠CAD = ∠DBC = 40°
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