Question
Download Solution PDFस्पीयरमैन श्रेणी में सहसंबंध गुणांक rs = 1 - \(\dfrac{6∑ d^2}{n(n^2-1)}\) है, संयुक्त श्रेणी के मामले में ∑d2 का अधिकतम मान है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है
संयुक्त श्रेणी के मामले में rs का मान = -1
गणना
यहाँ, स्पीयरमैन श्रेणी सहसंबंध गुणांक rs = -1
⇒ 1 - \(\dfrac{6∑ d^2}{n(n^2-1)}\) = -1
⇒ \(\dfrac{6∑ d^2}{n(n^2-1)}\) = 2
⇒ 6 \(∑ \)d2 = 2n(n2 - 1)
⇒ Σd2 = n(n2 - 1)/3
∴ संयुक्त श्रेणी के मामले में ∑d2 का अधिकतम मान है = \(\dfrac{1}{3}n(n^2 - 1)\)
Last updated on Jul 7, 2025
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