Question
Download Solution PDFदिए गए चित्र में, PAB एक छेदक है और PT, P से वृत्त की एक स्पर्श रेखा है। यदि PT = 8 सेमी, PA = 6 सेमी और AB = x सेमी है, तो x का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
PT = 8 सेमी
PA = 6 सेमी
प्रयुक्त सूत्र
PT2 = PA × PB
यहाँ, PT स्पर्शरेखा है
गणना:
माना AB "x" है
PT2 = PA × PB
82 = 6(6 + x)
32/3 = 6 + x
x = 14/3
AB का मान 14/3 सेमी है।
Last updated on Jul 12, 2025
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