Question
Download Solution PDFवितरण का मानक विचलन 5 है। चौथे केंद्रीय क्षण (मोमेंट) का मान, ताकि वितरण मेसोकोर्टिक हो जाये, होना चाहिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है
मानक विचलन σ = 5
संकल्पना
मेसोकोर्टिक के लिए β2 = 3
गणना
β2 = μ4/μ22
⇒ μ4/σ4 = 3 ( μ2 = विचरण = σ2)
⇒ μ4/54 = 3
⇒ μ4 = 625 × 3
∴ चौथे मोमेंट का मान 1875 है।
Last updated on Jul 8, 2025
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