Question
Download Solution PDFIf W = ϕ + iΨ represents the complex potential for an electric field.
Given \(\Psi =x^2-y^2 + \dfrac{x}{x^2 +y^2}\), then the function ϕ is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
From CR equations,
\(\frac{{\partial \phi }}{{\partial {\rm{x}}}} = \frac{{\partial {\rm{\psi }}}}{{\partial {\rm{y}}}}\)
\(\frac{{\partial \phi }}{{\partial {\rm{y}}}} = \frac{{\partial {\rm{\psi }}}}{{\partial {\rm{x}}}}\)
Calculation:
\(\frac{{\partial \phi }}{{\partial {\rm{x}}}} = \frac{\partial }{{\partial {\rm{y}}}}\left[ {{{\rm{x}}^2} - {{\rm{y}}^2} + \frac{{\rm{x}}}{{{{\rm{x}}^2} + {{\rm{y}}^2}}}} \right] = - 2{\rm{y}} - \frac{{2{\rm{xy}}}}{{{{\left( {{{\rm{x}}^2} + {{\rm{y}}^2}} \right)}^2}}}\)
Integrating w.r.t ‘x’ by keeping y constant
\(\Rightarrow \phi = {\rm{\;}} - 2{\rm{xy}} + \frac{{\rm{y}}}{{{{\rm{x}}^2} + {{\rm{y}}^2}}} + {\rm{C\;}}\)
\(\frac{{\partial {\rm{\psi }}}}{{\partial {\rm{y}}}} = \frac{\partial }{{\partial {\rm{x}}}}\left[ {{{\rm{x}}^2} - {{\rm{y}}^2} + \frac{{\rm{x}}}{{{{\rm{x}}^2} + {{\rm{y}}^2}}}} \right] = - 2{\rm{x}} - \frac{{{{\rm{x}}^2} - {y^2}}}{{{{\left( {{{\rm{x}}^2} + {{\rm{y}}^2}} \right)}^2}}}\)
Integrating w.r.t ‘y’ by keeping x constant
\( \Rightarrow \phi = {\rm{}} - 2{\rm{xy}} + \frac{{\rm{y}}}{{{{\rm{x}}^2} + {{\rm{y}}^2}}} + {\rm{C\;}}\)
Last updated on Jun 23, 2025
-> UPSC ESE result 2025 has been released. Candidates can download the ESE prelims result PDF from here.
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.