Question
Download Solution PDFA आणि B मिळून एक विशिष्ट कार्य 20 दिवसांत पूर्ण करू शकतात तर B आणि C मिळून ते कार्य 24 दिवसांत पूर्ण करू शकतात. जर A हा C पेक्षा दुप्पट चांगला कार्य करत असेल, तर B एकटा त्याच कार्याच्या 40% कार्य किती वेळात करेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
A = 2C
A + B हे 20 दिवसांत पूर्ण करतात
B + C हे 24 दिवसांत पूर्ण करतात
वापरलेली संकल्पना:
एकूण कार्य = कामगारांना लागलेल्या वेळेचा लसावि
गणना:
20 आणि 24 चा लसावि 120 आहे
तर, A आणि B ची कार्यक्षमता = 120/20 = 6 आणि B आणि C ची कार्यक्षमता = 120/24 = 5
आता 2C + B = 6 आणि B + C = 5
तर, C = 1
B = 4
40% कार्य = 120 × 2/5 = 48 एकक
तर, B ला 48/4 = 12 दिवस लागतील
∴ B एकटा समान कार्याचा 40% भाग 12 दिवसात पूर्ण करतो
Last updated on Jul 7, 2025
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