The expression for the RMS value of the current of a triangular wave form is:

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SSC JE Electrical 10 Oct 2023 Shift 2 Official Paper-I
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  1. \( \frac{\operatorname{Imax}}{2}\)
  2. \(\rm \sqrt{3} I_{\max }\)
  3. \( \frac{\operatorname{Imax}}{\sqrt{2}} \)
  4. \( \frac{\operatorname{Imax}}{\sqrt{3}}\)

Answer (Detailed Solution Below)

Option 4 : \( \frac{\operatorname{Imax}}{\sqrt{3}}\)
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Detailed Solution

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Concept

The RMS value of any signal is given by:

\(RMS=\sqrt{{1\over T}\int_{-\infty}^{\infty}x^2(t)\space dt}\)

where, T = Time period of the signal

Calculation

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\(RMS=\sqrt{{1\over T}\int_{0}^{T}({I_{max}\over T}t)^2\space dt}\)

\(RMS={I_{max}\over T}\sqrt{{1\over T}\int_{0}^{T}(t)^2\space dt}\)

\(RMS={I_{max}\over T}\sqrt{({t^3\over 3})_{0}^{T}}\)

\(RMS=\frac{\operatorname{Imax}}{\sqrt{3}}\)

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