The following graph shows the variation of displacement 'y' of a particle undergoing SHM with a quantity 'R'. Then 'R' is likely to be 

F1 Prabhu 20-09-21 Savita D2

  1. Kinetic energy of the particle
  2. Potential energy of the particle
  3. Total energy of the particle
  4. None of the above

Answer (Detailed Solution Below)

Option 3 : Total energy of the particle
Free
CRPF Head Constable & ASI Steno (Final Revision): Mini Mock Test
21 K Users
40 Questions 40 Marks 45 Mins

Detailed Solution

Download Solution PDF

The correct answer is option 3) i.e. Total energy of the particle

CONCEPT:

  • Simple harmonic motion (SHM): It is a type of oscillatory motion in which the restoring force is directly proportional to the displacement of the body from its mean position.
    • ​This means that the net force which in turn is the acceleration is proportional to the displacement of the object and acts in the opposite direction of the displacement.
    • The displacement in an SHM for a system starting at equilibrium (x = 0) is given by the equation:

⇒ x = asinωt

​​​Where x is the displacement, a is the amplitude, ω is the angular frequency and t is the time taken. 

  • The energy in simple harmonic motion: 
  • The kinetic energy is given by the equation: 

\(⇒ KE = \frac{1}{2}mω ^2 (a^2 - y^2)\)

  • The potential energy is given by the equation: 

\(⇒ PE = \frac{1}{2} mω ^2y^2\)

Where m is the mass, ω is the angular frequency, y is the displacement of the particle from the mean position and a is the amplitude.

EXPLANATION:

  • The given graph tells us that the quantity R is not dependent on displacement 'y'
  • The total energy of a particle executing SHM is the sum of its kinetic and potential energy.

The total energy, E = KE + PE

\(⇒ E = \frac{1}{2}mω ^2 (a^2 - y^2) + \frac{1}{2} mω ^2y^2\)

\(⇒ E = \frac{1}{2} mω ^2a^2\)

F1 Prabhu 20-09-21 Savita D3

  • It is inferred from the above equation that the total energy 'E' does not depend on the displacement of the particle 'y' in SHM.
  • Therefore, the quantity 'R' in the given graph represents the total energy of the particle.
Latest Indian Coast Guard Navik GD Updates

Last updated on Jul 4, 2025

-> The Indian Coast Guard Navik GD Application Correction Window is open now. Candidates can make the changes in the Application Forms through the link provided on the official website of the Indian Navy.

-> A total of 260 vacancies have been released through the Coast Guard Enrolled Personnel Test (CGEPT) for the 01/2026 and 02/2026 batch.

-> Candidates can apply online from 11th to 25th June 2025.

-> Candidates who have completed their 10+2 with Maths and Physics are eligible for this post. 

-> Candidates must go through the Indian Coast Guard Navik GD previous year papers.

More Oscillations Questions

Get Free Access Now
Hot Links: teen patti club apk teen patti flush teen patti master 2024