Two Capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be

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WBPSC JE Electrical 2018 (Held on 18th Feb 2018) Official Paper
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  1. 2C and 2V
  2. \(\rm \frac{C}{2}\ and \ \frac{V}{2}\)
  3. 2C and \(\rm \frac{V}{2}\)
  4. \(\rm \frac{C}{2}\ and \ 2V\)

Answer (Detailed Solution Below)

Option 4 : \(\rm \frac{C}{2}\ and \ 2V\)
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Detailed Solution

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Concept

Case 1:

When two capacitances are connected in series, their equivalent capacitance is given by:

\(C_{eq}={C_1C_2\over C_1+C_2}\)

In a series connection, the current remains the same and the voltage gets added.

Case 2:

When two capacitances are connected in parallel, their equivalent capacitance is given by:

\(C_{eq}={C_1+C_2}\)

In a parallel connection, the voltage remains the same and the current gets added.

Calculation

Given, C1 = C2 = C

In a series connection, their equivalent is given by:

\(C_{eq}={C \times C \over C+C}\)

\(C_{eq}={C \over 2}\)

Veq = V + V = 2V

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