Question
Download Solution PDFएक एकल कला अर्ध तरंग नियंत्रित दिष्टकारी की आपूर्ति 230 V, 50 Hz आपूर्ति के माध्यम से की जाती है। अधिकतम निर्गम वोल्टेज क्या संभव होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
1ϕ अर्ध-तरंग दिष्टकारी का औसत निर्गम वोल्टेज निम्न के द्वारा दिया जाता है:
\(V_{o(avg)} = {V_m \over 2\pi}(1+cosα)\)
जहाँ, Vo(avg) = निर्गम वोल्टेज का औसत मान
Vm = निवेश वोल्टेज का अधिकतम मान
α = फायरिंग कोण
गणना:
दिया गया है, आपूर्ति वोल्टेज = 230 V (RMS)
\(V_m = \sqrt{2}\times230\)
निर्गम वोल्टेज का अधिकतम मान α = 0° पर प्राप्त किया जाता है।
\(V_{o(avg)} = {\sqrt{2}\times 230 \over 2\pi}(1+cos0)\)
\(V_{o(avg)}=\frac{\sqrt{2}\times230}{\pi}\)
Last updated on Jun 2, 2025
-> HPCL Engineer 2025 notification has been released on June 1, 2025.
-> A total of 175 vacancies have been announced for the HPCL Engineer post in Civil, Electrical, Mechanical, Chemical engineering.
-> HPCL Engineer Online application will be activated from 1st June 2025 to 30th June 2025.
-> Candidates with a full-time engineering discipline in the relevant stream are eligible to apply.
-> The selection will be based on a Computer Based Test Group Task and/or Interview. Prepare for the exam using HPCL Engineer Previous Year Papers.