For the two-port network shown in the figure, the transmission parameter C is:

F4 Shubham 16-10-2020 Swati D2

This question was previously asked in
ESE Electronics 2014 Paper 1: Official Paper
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  1. Za
  2. \(1 + \frac{{{Z_a}}}{{{Z_b}}}\)
  3. Zb
  4. 1/Zb

Answer (Detailed Solution Below)

Option 4 : 1/Zb
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Detailed Solution

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Concept:

Transmission or ABCD parameters

General two-port network and Transmission parameters two-port network is shown below.

F1 S.B 1.9.20 Pallavi D2

Transmission 2 port network

F1 S.B 1.9.20 Pallavi D3

The direction of I2 is opposite to the standard form so it is taken as negative.

Transmission parameters are defined as:

\(\left[ {\begin{array}{*{20}{c}} {{V_1}}\\ {{I_1}} \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} A&B\\ C&D \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{V_2}}\\ { - {I_2}} \end{array}} \right]\)

V1 and I1 are dependent and V2 and I2 are independent.

Calculation:

From the ABCD parameters matrix, we get the following equations.

V= A V2 – B I2   ---(1)

I1 = C V2 - D I2   ---(2)

To calculate C, we open circuit the output terminal as shown:

F16 Shubham 30-11-2020 Swati D5

Using Equation (1), we get:

I1 = C V2 

\(C=\frac{I_1}{V_2}\)

Since I2 = 0, the current across Zb will be I1, i.e.

V2 = I1 × Zb

\(\frac{I_1}{V_2}=C=\frac{1}{Z_b}\)

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