While using a frequency counter for measuring frequency, two modes of measurement are possible. I) Period mode ii) Frequency mode. There is a ‘cross-over frequency’ below which the period mode is preferred. Assuming the crystal oscillator frequency to be 4 MHz the cross-over frequency is given by

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  1. 8 MHz
  2. 2 MHz
  3. 2 kHz
  4. 1 kHz

Answer (Detailed Solution Below)

Option 3 : 2 kHz
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Frequency meter:

  • Frequency meter is used to measure the frequency of periodic signals, by balancing two opposite forces.
  • Change in the frequency which is to be measured causes a change in the balance and measured by the deflection of pointer.
  • There are two modes of measurement that can be possible. Periodic mode and Frequency mode

 

Let fx = unknown frequency, fc = crystal frequency, fo = crossover frequency

Then, If fx < fo periodic mode

And fx > fo frequency mode

Now crossover frequency \({f_o} = \sqrt {{f_c}} \)

\( \Rightarrow {f_o} = \sqrt {4 \times {{10}^6}} Hz = 2 \times {10^3}Hz\)

⇒ fo = 2 kHz

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